WebDec 19, 2024 · If A1 is a YES, then A2:A10 should be restricted to date entry only. If A1 is a NO, then A2:A10 should allow text. So you want it to always accept values - you just want the values to only be restricted when the cell at the top of the column contains "No" To turn on Data Validation you could use VBA. Add this function to Sheet1: WebApr 1, 2024 · Enter the Criteria. Display the Data tab and find the Data Tools group. Press Data Validation to display the Data Validation dialog box and select the Settings tab. Select List from the Allow drop-down list. …
How to Make a Yes/No Drop-Down in Ex…
WebApr 5, 2024 · To add data validation in Excel, perform the following steps. 1. Open the Data Validation dialog box Select one or more cells to validate, go to the Data tab > Data Tools group, and click the Data Validation button. You can also open the Data Validation dialog box by pressing Alt > D > L, with each key pressed separately. 2. WebApr 7, 2024 · The following are the common Data Validation Types: Data Type Check Code Check Range Check Format Check Consistency Check Uniqueness Check Presence Check Length Check Look Up 1) Data Type Check A Data Type check ensures that data entered into a field is of the correct data type. A field, for example, may only accept numeric data. early childhood education course in india
Data Validation - Overview, Types, Practical Examples
WebSep 28, 2024 · If yes then you try below steps. Create a yes/no column, a choice column with choices 'End of the Day', 'High Priority', a date column. Then navigate to list settings -> Validation settings and use below formula to ensure form performs validation at all times. WebSep 29, 2024 · 0. So I am trying to validate whether the user typed in a Yes or No and to continue asking until they type in one or the other. This is my code so far. … WebSep 29, 2024 · Type Yes or No"); String input2 = scan.nextLine (); boolean d = input2.equalsIgnoreCase ("Yes") input.equalsIgnoreCase ("No"); // confirms if the user input is Yes/No or invalid other than that .... while (!d) { // d==false ' invalid user input System.out.println ("Invalid Input. css 按鈕樣式