Ifsin x + y log x + y then dy dx is
Web22 mrt. 2024 · If y = log(cos e x ), then dy/dx is : (a) cose (x-1) (b) e (-x) cos e x (c) e x sine x (d) -e x tan e x This question is inspired from Ex 5.4, 5 - Chapter 5 Class 12 - Continuity and Differentiability Web10 jul. 2016 · 1 Answer Eddie Jul 10, 2016 y = x −1 + C ex Explanation: dy dx = x − y not separable, not exact, so set it up for an integrating factor dy dx +y = x the IF is e∫dx = ex so ex dy dx +exy = xex or d dx (exy) = xex so exy = ∫xex dx for the integration, we use IBP: ∫uv' = uv − ∫u'v u = x,u' = 1 v' = ex,v = ex ⇒ xex −∫ex dx = xex − ex +C
Ifsin x + y log x + y then dy dx is
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WebWhat is dy/dx if y = e ^ (x (1 + log x))? Given y = e ^ (x (1 + log x)) Differentiating both side with respect to x, we have:— d (y)/d (x) = d {e^ (x (1 + log x))}/d (x) Using Chain Rule, we have: d (y)/d (x) = d {e^ (x (1 + log x))}/d (x (1 + log x) * d (x (1 + log x))/d ( x) Using … Web1 feb. 2024 · Best answer. Given, xy = yx. Taking logarithm on both sides, we get. y log x = x log y. Differentiating both sides, w.r.t. x. y.(1/x) + log x(dy/dx) = x.(1/y).(dy/dx) + log y. 1. (y/x) + (log x).(dy/dx) = (x/y).(dy/dx) + log y. (dy/dx)[log x - (x/y)] = log y - (y/x) …
WebThen the product form is CH three ch you. This is as he tell the high this is a solitary D hide. So option it, correct. So option A is correct answer for this problem.. answer from Narayan Hari 4. Answers #5 Right for both of these. If we have an alcohol that reacts with a carb oxalic acid, we know it will produce an Esther.
Web22 mei 2024 · Given: siny + x = logx To Find: Find dy/dx Solution: The given equation is siny +x= logx before differentiating the given equation we should know the differentiation of sinx, x and logx which is cosx, 1 and 1/x respectively. Now … Web9 aug. 2024 · Find y d d y d x where y = log sin(log x) y = log sin ( log x) asked Apr 14, 2024 in Differentiation by Garimak (73.0k points) class-12. differentiation. 0 votes. 1 answer. If y = log{( 1 + x 1 − x)1 /4} − 1 2 tan−1 x, then dy dx = y = log { ( 1 + x 1 - x) 1 / 4 } - 1 …
WebSolution Let y = (log x) x + x log x Also, let u = (log x) x and v = x log x ∴ y = u + v dy dx du dx dv dx ⇒ dy dx = du dx + dv dx ........ (1) u = (logx) x ⇒ log u = log [ (log x) x] ⇒ log u = x log (log x) Differentiating both sides with respect to x, we obtain
Web28 jun. 2024 · If ` y= (log x) ^(logx) ,then (dy)/(dx)=` the life story of prophet muhammad for kidsWebGiven, xx = yyTaking log on both sides, we getx log x = y log yDifferentiating w.r.t. y, we gety.y1.dxdy +logydxdy = xx1 + logx⇒ dxdy (1+logy)= 1+ logx⇒ dxdy = 1+logy1+logx. ticinocom hostingWebLet y=log(log(x)) then find dxdy. Easy Solution Verified by Toppr Given, y=log(log(x)) Now differentiating both sides with respect to x we get, dxdy= logx1. x1. Solve any question of Continuity and Differentiability with:- Patterns of problems > Was this answer helpful? 0 0 … the life story of nelson mandelaWeb18 jun. 2024 · If sin y + x = log x, then dy/dx is A) 1/ (x cos y) B) 1/ (x sin y) C) (1- x)/ (x cos y) D) (1+ x)/ (x sin y) - Brainly.in. AniketSingh2910. 18.06.2024. Math. Secondary School. answered • expert verified. ticino for financeWeb13 mrt. 2024 · If y = sin (log x), then prove that x^2 (d^2y)/dx^2+dy/dx+y = 0. - Sarthaks eConnect Largest Online Education Community. If y = sin (log x), then prove that x^2 (d^2y)/dx^2+dy/dx+y = 0. If y = sin (log x), then prove that x2 d2y dx2 + x 2 d 2 y d x 2 … tic in neckWebSin(x+y)=log(x+y).....dxd [sin(x+y)]=dxd [log(x+y).....cos(x+y)dxd (x+y)=x+y1 dxd (x+y).....cos(x+y)(1+dxdy )=x+y1 (1+dxdy ).....cos(x+y)(1+dxdy )−x+y1 (1+dxdy )=0 ... ticino fiume wikipediaWebCalculus Find dy/dx y = natural log of x^2 y = ln (x2) y = ln ( x 2) Differentiate both sides of the equation. d dx (y) = d dx (ln(x2)) d d x ( y) = d d x ( ln ( x 2)) The derivative of y y with respect to x x is y' y ′. y' y ′ Differentiate the right side of the equation. Tap for more steps... 2 … the life story of shatta wale