Witryna2 gru 2024 · 解决问题:hive中count(distinct) over() 无法使用场景 累计去除统计,实际经常使用到的场景比如会员每日历史累计消费,项目每日累计营收等。案例: 数据准备: 用户轨迹用户访问日志表 test_visit_tab cookieid(用户id) uvdate(访问时间) pagename(浏览页面) pv(访问次数) cookie1 2024-02-01 A_page 1 cookie1 2024-02-01 B_page 2 ... WitrynaImpala only supports the CUME_DIST() function in an analytic context, not as a regular aggregate function. Examples: This example uses a table with 9 rows. The …
Count distinct not allowed in Analytical function in Impala
WitrynaAPPX_COUNT_DISTINCT Query Option ( Impala 2.0 or higher only) When the APPX_COUNT_DISTINCT query option is set to TRUE, Impala implicitly converts COUNT (DISTINCT) operations to the NDV () function calls. The resulting count is approximate rather than precise. WitrynaCOUNT([DISTINCT ALL] expression) [OVER (analytic_clause)] Depending on the argument, COUNT() considers rows that meet certain conditions: The notation … north america qualifying
hadoop - Hive/Impala count distinct on a partitioned column results in ...
Witryna26 cze 2012 · Jun 26, 2012 at 10:19. Add a comment. 1. There is a solution in simple SQL: SELECT time, COUNT (DISTINCT user) OVER (ORDER BY time) AS users FROM users. =>. SELECT time, COUNT (*) OVER (ORDER BY time) AS users FROM ( SELECT user, MIN (time) AS time FROM users GROUP BY user ) t. Share. Witryna16 lip 2024 · The notation COUNT (column_name) only considers rows where the column contains a non- NULL value. You can also combine COUNT with the DISTINCT operator to eliminate duplicates before counting, and to count the combinations of values across multiple columns. 根据count ()括号里的表达式不同计算的东西也不同. count (*) 代表 ... WitrynaCOUNT (DISTINCT rx.drugName) over (partition by rx.patid,rx.drugclass) as drugCountsInFamilies which SQL complains about. But you can do this instead: … north america pyramid locations